E.m.f of the following cell at $298 K$ in $V$ is $x \times 10^{- 2} .$
$Zn | {Zn}^{2 +} (0.1 M) | | {Ag}^{+} (0.01 M) | Ag$
The value of x is _________. (Rounded off to the nearest integer)
$Given : E_{{Zn}^{2 +} / Zn}^{°} = - 0.76; E_{{Ag}^{+} / Ag}^{°} = + 0.80 V; 2.303 \frac{RT}{F} = 0.059$

Open in App

Solution

$Step 1 : Calculation of E °_{cell} {E °}_{cell} = {E °}_{Ag / {Ag}^{+}} - E °_{{Zn}^{2 +} / Zn} = 0.80 - (- 0.76) = 1.56 V Step 2 : Calculation of Emf of cell i . e . E_{cell} Using Nernst Equation, E_{cell} = E °_{cell} - \frac{0.059}{2} \log \frac{[{Zn}^{2 +}]}{{[{Ag}^{+}]}^{2}} = 1.56 - \frac{0.059}{2} \log \frac{[0.1]}{{[0.01]}^{2}} {Substituting the given values} = 1.56 - \frac{0.059}{2} \log 3 = 1.56 - 0.0885 = 1.4715 = 147.15 \times 10^{- 2} ≃ 147 \times 10^{- 2} = x \times 10^{- 2} Hence, the value of x is 147.15 V ≃ 147 V .$

Suggest Corrections

Similar questions

Study the following pattern and write the next steps for given pattern:
$1 \times 9 + 2 = 11 12 \times 9 + 3 = 111 123 \times 9 + 4 = 1111 1234 \times 9 + 5 = 11111___+____=__________+____=_______$

To draw a histogram to represent the following frequency distribution:

Class interval	Frequency
$5 - 10 10 - 15 15 - 25 25 - 45 45 - 75$	$6 12 10 8 15$

The adjusted frequency for the class $25 - 45$ is

Study the pattern and answer the following:

$15 \times 15 = 225 25 \times 25 = 625 35 \times 35 = 1225 45 \times 45 = 2025$

$55 \times 55 = . . . . 25 65 \times 65 = . . . . 25 75 \times 75 = . . . . 25 85 \times 85 = . . . . 25 95 \times 95 = . . . . 25 105 \times 105 = . . . . 25$

Study the following pattern and write the next two steps for given pattern:
$43 \times 9 = 43 (10 - 1) = 430 - 43 43 \times 99 = 43 \times (100 - 1) = 4300 - 43 43 \times 999 = 43 \times (1000 - 1) = 43000 - 43___\times____=__\times____=_____-_________\times____=__\times____=_____-______$

Multiply

$4 2 \times 9______________________$

Join BYJU'S Learning Program

E.m.f of the following cell at 298K in V is x×10-2.Zn|Zn2+(0.1M)||Ag+(0.01M)|AgThe value of x is _________. (Rounded off to the nearest integer)Given:EZn2+/Zn°=-0.76;EAg+/Ag°=+0.80V;2.303RTF=0.059

E.m.f of the following cell at $298 K$ in $V$ is $x \times 10^{- 2} .$
$Zn | {Zn}^{2 +} (0.1 M) | | {Ag}^{+} (0.01 M) | Ag$
The value of x is _________. (Rounded off to the nearest integer)
$Given : E_{{Zn}^{2 +} / Zn}^{°} = - 0.76; E_{{Ag}^{+} / Ag}^{°} = + 0.80 V; 2.303 \frac{RT}{F} = 0.059$