wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the angle between the lines vector r=2i-3j+k+li+j+3k and vector =i-j-k+μ2i-3j+k


A

π2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

cos-1991

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

cos-12154

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

π3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

cos-12154


Explanation for correct answer:

Find the angle:

Given, vectors r=2i-3j+k+li+j+3k and i-j-k+μ2i-3j+k

We know that the angle between two vectors a&b is cos(θ)=a·b|a||b|

Required angle is cosθ=i+j+3k·2i-3j+k12+12+32×22+-32+12

cosθ=2-3+311×14

cosθ=2154

θ=cos-12154

Hence, correct answer is option (C).


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon