Find the area of the triangle with vertices (2,3), (0,1), and (1,2)
12 square unit
0 square unit
2 square unit
212 square unit
Finding the area of triangle:
Let the points be, A(2,3), B(0,1) andC(1,2), then
Area of the triangle in determinant form is given by
12x1y11x2y21x3y31
Here,
x1=2,x2=0,x3=1,y1=3,y2=1,y3=2
putting these values, we get
=12231011121=12[2(1-2)-3(-1)+1(-1)]=12(-2+3-1)=12(3-3)=12(0)=0
Hence the correct option is (B).
Using vectors, find the area of the triangle with vertices A(1, 1, 2), B(2, 3, 5) and C(1, 5, 5)
Using vectors, find the area of the triangle with vertices A(1, 2, 3), B(2, -1, 4) and C(4, 5, -1)