Question

For the circuit shown below, the Boolean polynomial is

• A. $(~p\vee q)\vee (p\vee ~q)$
• B. $(~p\wedge q)\wedge (p\wedge q)$
• C. $(~p\wedge ~q)\wedge (q\wedge p)$
• D. $(~p\wedge q)\vee (p\wedge ~q)$

Answer 1

The correct option is D

$(~p\wedge q)\vee (p\wedge ~q)$

Explanation for correct option.

Boolean Polynomial.

In Boolean polynomial 'and' is represented as $\wedge$ & or is represented as$\vee$

Determining value

Since, $~p\&q$ are in series

Therefore, $~p\wedge q$

Also, $p\&~q$ are in series

Therefore, $p\wedge ~q$

Therefore the required Boolean polynomial is, $(~p\wedge q)\vee (p\wedge ~q)$

Hence, correct option is $\mathbf{\left(}\mathit{D}\mathbf{\right)}$