For the reaction,

Na2CO3 + 2HCl → 2NaCl + H2O + CO2,

The equivalent weight of Na2CO3 is:

A. M/2

B. M

C. 2 M

D. M/4

Solution: (C)

The reaction is as:

Na2CO3 + 2HCl → 2NaCl + H2O + CO2

Let weight of Na2CO3 be M.

In this reaction, 1 mole of sodium carbonate reacts with 2 moles of hydrochloric acid or 2 equivalents of HCl.

Therefore, 21 moles of Na2CO3 is equivalent to the equivalent mass of Na2CO3

Hence, the equivalent mass of sodium carbonate is 2M.

Was this answer helpful?


0.5 (3)


Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published.