Na2CO3 + 2HCl → 2NaCl + H2O + CO2,
The equivalent weight of Na2CO3 is:
C. 2 M
The reaction is as:
Na2CO3 + 2HCl → 2NaCl + H2O + CO2
Let weight of Na2CO3 be M.
In this reaction, 1 mole of sodium carbonate reacts with 2 moles of hydrochloric acid or 2 equivalents of HCl.
Therefore, 21 moles of Na2CO3 is equivalent to the equivalent mass of Na2CO3
Hence, the equivalent mass of sodium carbonate is 2M.