For the reaction,

Na2CO3 + 2HCl → 2NaCl + H2O + CO2,

The equivalent weight of Na2CO3 is:

A. M/2

B. M

C. 2 M

D. M/4

Solution: (C)

The reaction is as:

Na2CO3 + 2HCl → 2NaCl + H2O + CO2

Let weight of Na2CO3 be M.

In this reaction, 1 mole of sodium carbonate reacts with 2 moles of hydrochloric acid or 2 equivalents of HCl.

Therefore, 21 moles of Na2CO3 is equivalent to the equivalent mass of Na2CO3

Hence, the equivalent mass of sodium carbonate is 2M.

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