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Question

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.

Assertion A: Body P having mass M moving with speed ‘u’ has head-on collision elastically with another body ‘Q’ having mass ‘m’ initially at rest. If m<<M, body ‘Q’ will have a maximum speed equal to ‘2u’ after collision.

Reason R: During elastic collision, the momentum and kinetic energy are both conserved.

In the light of the above statements, choose the most appropriate answer from the options given below:


A

A is correct but R is not correct.

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B

Both A and R are correct but R is NOT the correct explanation of A

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C

A is not correct but R is correct.

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D

Both A and R are correct and R is the correct explanation of A.

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Solution

The correct option is D

Both A and R are correct and R is the correct explanation of A.


Step 1. Given data :

The mass of a bodyP is M.

The mass of a body Q ism.

Where m<<M.

The velocity of bodyP is u before the collision

Step 2. Solving for the maximum velocity of Q after collision

An elastic collision is a collision in which there is no net loss in kinetic energy in the system as a result of the collision.

Both momentum and kinetic energy are conserved quantities in elastic collisions.

From momentum conservation, second body at rest initially we have

m1v1=m1v'1+m2v'2

Kinetic energy we have12m1v21=12m1v'21+12m2v'22

The velocity of second body after collision

v2'=2m1m1+m2v1v2'=2MM+mu

now since M>>m, we have

v2'=2MMu=2u

Where M is mass of Body P having with initial velocity u and body ‘Q’ having mass ‘m’ initially at rest. After collision body P have velocity v'1 and body Q have velocity v2' .

So, From conservation of momentum and kinetic energy equation was derived which gave velocity of second particle after collision to be 2u. So, both the assertion and reason are correct and reason explains the assertion.

Hence, option D is correct.


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