Question

How do you Convert $\mathrm{Benzene}$ to $\mathrm{Bromobenzene}$

Answer 1

1. In the presence of Lewis acid catalysts, such as $\mathrm{ferric}\mathrm{bromide}$ is prepared by the action of $\mathrm{bromine}$ on $\mathrm{benzene}$ . To add a phenyl group into other molecules is used. One procedure requires the conversion to phenyl $\mathrm{magnesium}\mathrm{bromide}$, the Grignard reagent.
2. $\mathrm{Bromobenzene}$ is not an alkyl halide since it is bound to the ${\mathrm{sp}}^2$ carbon of a benzene ring by a halogen atom ($\mathrm{bromine}$). This means a secondary alkyl halide is the molecule. The carbon that the $\mathrm{chlorine}$ is bound to be bonded closely to three other carbons with ${\mathrm{CH}}_3-\mathrm{CCl}\left({\mathrm{CH}}_3\right)-{\mathrm{CH}}_3$ ($2-\mathrm{chloro}-2-\mathrm{methylpropane}$), rendering it a tertiary alkyl halide.