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Question

Identify the option where all four molecules possess a permanent dipole moment at room temperature.


A

BF, O3, SF6, XeF6

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B

BeCl2, CO2, BCl3, CHCl3

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C

SO2, C6H5Cl, H2Se, BrF5

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D

NO2, NH3, POCl3, CH3Cl

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Solution

The correct option is D

NO2, NH3, POCl3, CH3Cl


Dipole moments occur when there is a separation of charge. They can occur between two ions in an ionic bond or between atoms in a covalent bond; dipole moments arise from differences in electronegativity. The larger the difference in electronegativity, the larger the dipole moment. The size of a dipole is measured by its dipole moment (μ).

  • We know that the polar character is the separation of negative and positive charges in a compound and the measurement of this polar character of a chemical bond in a molecule or between two atoms is given by the dipole moment.
  • We know that the separation of charges will lead to the formation of a dipole moment and the main reason for the development of a dipole moment is the differences in electronegativity between the chemically bonded atoms.

For symmetrical molecule μ = 0

For unsymmetrical molecule μ ≠ 0

An explanation for the correct option:

(C) SO2, C6H5Cl, H2Se, BrF5

In this option, all molecules have a nonzero dipole moment and hence they possess a permanent dipole moment.

(d) NO2, NH3, POCl3, CH3Cl

In this option, all molecules have a nonzero dipole moment and hence they possess a permanent dipole moment.

An explanation for the incorrect option:

(a) BF3, O3, SF6, XeF6

In this option, the net dipole moment of the molecules BF3 and SF6 is zero and hence they do not possess a permanent dipole moment.

(b) BeCl2, CO2, BCl3, CHCl3

In this option, the net dipole moment of the molecules BeCl2, BCl3, and CO2 is zero and hence they do not possess a permanent dipole moment.

Final Answer: options C and D both are correct because both show zero dipole moment at room temperature.


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