If λ(3i+2j-6k) is a unit vector, then the values of λ are:
±17
±7
±43
±143
Explanation for the correct option:
Find the value of λ:
Given, λ(3i+2j-6k)=1
⇒ λ3i+2j-6k=1
⇒λ32+22+-62=1
⇒ λ9+4+36=1
⇒ λ49=1
⇒ λ×±7=1
∴λ=±17
Hence, Option ‘A’ is Correct.
Ifis a nonzero vector of magnitude ‘a’ and λ a nonzero scalar, then λis unit vector if
(A) λ = 1 (B) λ = –1 (C)
(D)