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Question

If A=[-1,1]andf:AAis defined as f(x)=x|x|, for all xbelongs to A, then f(x) is


A

many-oneandintofunction

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B

one-oneandintofunction

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C

many-oneandontofunction

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D

one-oneandontofunction

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Solution

The correct option is D

one-oneandontofunction


Explanation for correct option:

Finding type of relation.

Given that A=[-1,1]andf:AAis define as f(x)=x|x|,xA

f(x)=x2forx>0andf(x)=x2forx<0

f(x)=x2 ranges from 0to1, when x ranges from ranges from 0to1, also f(x)=-x2 ranges from 0to-1, when x ranges from 0to-1.

The function is one-one and onto.

Hence, correct option is d


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