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Question

If A and B are two events such thatP(AUB)+P(A∩B)=78, and P(A)=2P(B), then P(A)=


A

712

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B

724

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C

512

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D

1724

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Solution

The correct option is A

712


Explantion for the correct option:

Finding the value of P(A):

P(AUB)+P(A∩B)=78 and

P(A)=2P(B) ....1

We know that, P(AUB)=P(A)+P(B)-P(A∩B)

P(AUB)+P(A∩B)=P(A)+P(B)

=P(A)+P(A)2 ( from 1)

78 =3P(A)2

P(A) = 712

Hence, option "A" is correct.


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