IfA,B are two events and P(A')=0.3,P(B)=0.4and P(A∩B')=0.5, then P(A∪B')is equal to
0.5
0.8
1
0.1
Find the value of P(A∪B'):
Given that and P(A')=0.3,P(B)=0.4and P(A∩B')=0.5
⇒P(A)=1-P(A')=1-0.3=0.7
⇒P(B')=1-P(B)=1–0.4=0.6
Now, substitute the values, we get
P(A∪B')=0.7+0.6–0.5⇒P(A∪B')=0.7+0.1⇒P(A∪B')=0.8. P(A∪B')=P(A)+P(B')–P(A∩B')
Hence, the correct option is (B).