If a, b, c are +ve, then a^2 + b^2 + c^2 is

1) > a + b + c

2) > ab + bc + ca

3) < a + b + c

4) < ab + bc + ca

Solution: (2) > ab + bc + ca

[a² + b²] / 2 > √a²b² [AM > GM] [a² + b²] > 2ab

[b² + c²] > 2bc

[c² + a²] > 2ca

2 (a² + b² + c²) > 2 [ab + bc + ca]

(a² + b² + c²) > [ab + bc + ca]

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