If a, b, c are +ve, then a2 + b2 + c2 is

1) > a + b + c

2) > ab + bc + ca

3) < a + b + c

4) < ab + bc + ca

Solution: (2) > ab + bc + ca

[a2 + b2] / 2 > √a2b2 [AM > GM] [a2 + b2] > 2ab

[b2 + c2] > 2bc

[c2 + a2] > 2ca

2 (a2 + b2 + c2) > 2 [ab + bc + ca]

(a2 + b2 + c2) > [ab + bc + ca]

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