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Question

If a tangent to the curvey=6xx2 is parallel to the line4x2y1=0, then the point of tangency on the curve is


A

(2,8)

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B

(8,2)

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C

(6,1)

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D

(4,2)

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Solution

The correct option is A

(2,8)


Find the point of tangency:

Given the curve y=6xx2

dydx=62x

The tangent is parallel to the line 4x2y1=0

4-2dydx=0dydx=4262x=4262x=2x=2

and y=8

The required point of tangency will be (2,8).

Hence, the correct option is A.


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