If a1,a2,...a10be in AP, 1h1,1h2,...1h10 be in AP. a1=h1=2and a10=h10=3 then a4h7=?
Explanation for the correct option:
Step 1. Find the Value of a4h7
Given a1,a2,..a10and h1,h2,..h10 are in
a1=h1=2a10=h10=3
Step 2. Finding a4
a10=a1+(10-1)d1
⇒3=2+9d1
⇒d1=19
a4=a1+3d1=2+3×19=2+13=73
Step 3. Finding h7
1h10=1h1+9d2
⇒ 13=12+9d2
⇒ d2=-154
⇒ 1h7=1h7+6d2
⇒ 1h7=12+6×(-154)
⇒ 1h7=12-19=718
⇒ h7=187
Step 4. Multiply a4 and h7
a4h7=73×187=6
Hence, the value of a4h7 is 6
Let a1,a2,............a10 be in AP and h1, h2..............h10 be in H.P. If a1 = h1 = 2 and a10 = h10 = 3, then a4h7 is