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Question

Ifa.i=4, then (a.j)Γ—(2j-3k)=?


A

12

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B

2

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C

0

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D

-12

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Solution

The correct option is D

-12


Explantion for the correct option:

Find out: (a.j)Γ—(2j-3k)=?

Given

a.i=4

(a.j)Γ—(2j-3k)=a.(jΓ—2j-3k)=a.(jΓ—2j-3jΓ—k)=a.(0-3i){jΓ—j=0&jΓ—k=i}=a.{-3(i)}=-3(a.i)=-3(4)∡a.i=4=-12

Hence, the option (D) is correct.


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