Ifa=i+j+k,b=i+j,c=iand(axb)xc=λa+μb,thenthevalueofλ+μis?
0
1
2
3
Explanation of the correct option:
Given, a=i+j+k,b=i+j,c=i
(axb)xc=(a.c)b-(b.c)a=b-a
Given, (axb)xc=λa+μb
b-a=λa+μb
Now if we compare both the sides, we get;
λ+μ=0andλ=-1&μ=1
Therefore, the value of λ+μ=0.
Hence, option (A) is the correct answer.