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Question

If ax2-y2+4x-y=0 represents a pair of lines, then a is equal to


A

-16

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B

16

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C

-4

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D

4

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Solution

The correct option is B

16


Find the value of a:

Given ax2-y2+4x-y=0

Comparing the given equation with the general equation

ax2+2hxy+by2+2gx+2fy+c=0

We get a=a,h=0,b=-1,g=2,f=-1/2,c=0

abc+2fgh–af2–bg2–ch2=0 represents a pair of straight lines.

⇒0+0–a/4+4+0=0⇒-a/4=-4⇒a=16

Hence the correct option is B.


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