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Question

Ifcosɑcoshβ=1, then β=?


A

logsec(ɑ/2)

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B

logtanɑ

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C

log(secɑ+tanɑ)

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D

logsin(ɑ/2)

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Solution

The correct option is C

log(secɑ+tanɑ)


Find the value β:

cosɑcoshβ=1coshβ=secɑβ=cosh-1(secɑ)=log(secɑ+sec2ɑ-1)=log(secɑ+tanɑ)

Hence, the correct answer is option (C).


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