If △r=2r-1Crm1m2-12mm+1sin2msin2msin2m+1 then the value ∑r=0m△r=
1
0
2
None of these
Explanation for the correct option:
Find the value of ∑r=0m△r:
Given,
△r=2r-1Crm1m2-12mm+1sin2msin2msin2m+1
Now the value of
∑r=0M△r=∑r=0M2r-1∑r=0MCrM∑r=0M1M2-12MM+1sin2Msin2Msin2M+1=M2-12MM+1M2-12MM+1sin2Msin2Msin2M+1
∴∑r=0M△r=0 ∵R1=R2
Hence, Option ‘B’ is Correct.