If density of earth increased 4 times and its radius became half of what it is, our weight will

1) Be four times its present value

2) Be doubled

3) Remain same

4) Be halved

Answer: 2) Be doubled

Solution:

Weight, W = mg = m G (4/3) π R ρ

Now that, R’ = R/2

and ρ’ = 4ρ

W’ = m G (4/3) π (R/2) 4ρ

(W’/W) = [m G (4/3) π (R/2) 4ρ]/[m G (4/3) π R ρ]

= (1/2) x 4 = 2

W’ = 2W

Therefore, the weight will be doubled

Was this answer helpful?

 
   

0 (0)

(0)
(0)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *

*

*

Ask
Question