If ∫uv''dx=uv'-vu'+a, then a=
∫uv''dx
∫u'vdx
∫uv'dx
∫u''vdx
Explanation for the correct option.
Find the value of a.
The integration by parts is given as: ∫uv'dx=uv-∫u'vdx.
So using that the integral ∫uv''dx can be solved as:
∫uv''dx=uv'-∫u'v'dx=uv'-u'v-∫u''vdx=uv'-u'v+∫u''vdx
It is given that ∫uv''dx=uv'-vu'+a, so the value of a is ∫u''vdx.
Hence, the correct option is D.