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Question

If logkx·log5k=logx5,k1,k>0, then x is equal to:


A

k

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B

0

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C

5

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D

None of these

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Solution

The correct option is C

5


Explanation for the correct option:

Given logkx·log5k=logx5 wherek1,k>0

We know that, logb(a)=log(a)log(b)

So,

logxlogk·logklog5=log5logxlogx2=log52logx=log5x=5

Hence, option(C) i.e.5, is the correct answer.


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