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Question

If m1,m2,m3,m4 are respectively the magnitudes of the vectors a1=2i-j+k,a2=3i-4j-4k,a3=-i+j-k,a4=-i+3j+k, then the correct order of m1,m2,m3,m4 is;


A

m3<m1<m4<m2

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B

m3<m1<m2<m4

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C

m3<m4<m1<m2

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D

m3<m4<m2<m1

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Solution

The correct option is A

m3<m1<m4<m2


Explanation for the correct answer:

Given, a1=2i-j+k,a2=3i-4j-4k,a3=-i+j-k,a4=-i+3j+k

We know that the magnitude of vector is given by x2+y2+z2

So,

m1=22+(-1)2+(1)2=6m2=32+(-4)2+(-4)2=41m3=(-1)2+12+(-1)2=3m4=(-1)2+32+12=11

So, m3<m1<m4<m2

Therefore, option (A) is the correct answer.


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