If z-z¯+z+z¯=2, then z lies on
a circle
a square
an ellipse
a line
The explanation for the correct option:
Let us assume that z=x+iy, where i=-1.
Thus, z¯=x-iy.
It is given that, z-z¯+z+z¯=2
⇒x+iy-x+iy+x+iy+x-iy=2⇒2iy+2x=2⇒2y2+2x2=2⇒2x+2y=2⇒x+y=1
As x+y=1 is an equation of a square, thus z lies on a square.
Hence, (B) is the correct option.