Ifp,q,r are simple propositions with truth values T,F,Tthen the truth value of [(~p∨q)∧~r]⇒p is
True
False
True, if r is false
None of these
Explanation for the correct option
p,q,r are simple propositions with truth values T,F,T
⇒~p∨qmeansF∨F=F⇒~rmeansF∴[(~p∨q)∧~r)=F∧F=FWherep=TmeansF⇒T=T.
The true value of the given statement is True
Hence option ‘a’ is correct.