wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If R and H represent horizontal range and maximum height of the projectile, then the angle of projection with the horizontal is


A

tan1HR

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

tan12HR

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

tan14HR

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

tan14RH

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

tan12HR


Explanation for the correct option:

Step 1: Apply the formula of projectile motion

In a projectile motion, the maximum height is given by H=u2sin2θ2g.......i

and the horizontal range is R=u2sin2θ2g=2u2sinθcos2g.......ii

Where, u is the velocity of the projectile, which makes an angle θ with the horizontal component.

Step 2: Divide equation (i) by (ii), and we get

HR=u2sin2θ2g2u2sinθcos2gHR=u2sin2θ2g×2g2u2sinθcosHR=sinθ2cosθHR=tanθ2tanθ=2HRθ=tan12HR

Therefore, the angle of projectile is tan12HR.

Hence, the correct option is (B).


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Projectile on an Incline
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon