If S(p,q,r)=(~p)∨[~(q∧r)] is a compound statement, then S(~p,~q,~r) is
~S(p,q,r)
S(p,q,r)
p∨(q∧r)
p∧(q∨r)
S(p,q,~r)
Explanation for the correct option.
Given, S(p,q,r)=(~p)∨[~(q∧r)].
S(~p,~q,~r)=~~p∨[~~q∧~r]=p∨[~(~q)∨~(~r)]=p∨(q∨r)
Hence, option C is correct.