wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If t=v22, then -dfdt is equal to, (where f is acceleration)


Open in App
Solution

Explanation for the correct answer:

Finding the differentiation:

t=v22v2=2t

Differentiating both sides with respect to t, we get

2vdvdt=2dvdt=1v...1

We know that acceleration is the rate of change of velocity then

dvdt=f...2

From 1 and 2 we get,

vf=1

By differentiating the above equation with respect to t, then

vdfdt+fdvdt=0[d(xy)dt=xdydt+ydxdt]dfdt+dvv2dt=0dfdt=-dvv2dt-dfdt=1v3[from1]-dfdt=f3

Hence, the value of a derivative is f3.


flag
Suggest Corrections
thumbs-up
12
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
All Strings Attached
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon