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Question

If the coefficient of mutual induction of the primary and secondary coils of an induction coil is 5 H and a current of 10 A is cut-off in 5×10-4 s, the emf inducted (in volt) in the secondary coil is


A

5×104

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B

1×105

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C

25×105

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D

5×106

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Solution

The correct option is B

1×105


Step 1: Given data

Coefficient of mutual induction, M = 5 H

Change in current, di = 10 A

Change in time, dt = 5×10-4 s

Step 2: Formula used

Induced emf in the secondary coil = εs=-Mdidt

Step 3: Calculation

εs=-Mdidt

=-5105×10-4

=1×105 V [The negative sign only indicates that the emf opposes the change.]

The emf induced in the secondary coil is 1×105 V.

Hence option B is the correct answer.


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