If the integrating factor of the differential equation dydx+Pxy=Qx is x, then Px is
x
x22
1x
1x2
12x
Explanation for the correct option:
The given differential equation, dydx+Pxy=Qx.
The integrating factor, e∫Pxdx=x.
⇒∫Pxdx=logx⇒ddx∫Pxdx=ddxlogx⇒Px=1x
Therefore the value of Px is 1x.
Hence, option (C) 1x is the correct answer.