wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If the median AD of a triangle ABC divides the angle BAC in the ratio 1:2, then sinBsinC is equal to


A

2cosA3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

12secA3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

12sinA3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

2cscA3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

12secA3


Explanation of the correct option.

Compute the required value.

From sine rule in ABD,

ADsinB=BDsinA3……………1

From sine rule in ADC,

ADsinC=CDsin2A3…………2

Divide equation 2 by equation 1,

sinBsinC=sinA3sin2A3sinBsinC=sinA32sinA3cosA3sinBsinC=12cosA3sinBsinC=12secA3

Hence option B is the correct option.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Angle between a Plane and a Line
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon