If the numbers a,b,c,d and e are in the form of an AP with a=1, then a-4b+6c-4d+e is equal to
1
2
0
3
Explanation for correct option:
Given that the numbers a,b,c,d and e are in AP. and a=1
Let the common difference be h
∴b=a+h=1+h∴c=a+2h=1+2h∴d=a+3h=1+3h∴e=a+4h=1+4h
∴a-4b+6c-4d+e=1-41+h+61+2h-41+3h+1+4h=1-4-4h+6+12h-4-12h+1+4h=0
Hence, option C is correct answer.