If the straight line ax+by+c=0 always passes through (1,-2), then a,b,c are
In A.P.
In H.P.
In G.P.
None of these.
Explanation for the correct option.
Given: ax+by+c=0 passes through (1,-2).
⇒a-2b+c=0⇒2b=a+c
From the basic definition of A.P we can see that a,b,c are in A.P.
Hence option(A) i.e. In A.P. is the correct option.
If the straight line ax+by+c=0 passes through (1,-2) then a,b,c are in,
if a,b,c are in A.P , then prove that the straight line ax+by+c=0 will always pass through the point (1,-2)