If x2+y2=1, then
yy''-2(y')2+1=0
yy''+(y')2+1=0
yy''-(y')2+1=0
yy''+2(y')2+1=0
Explanation for the correct option:
Differentiation of circle equation:
By differentiating x2+y2=1 w.r.t x, we get
2x+2yy'=0
Again differentiating it w.r.t x, we get
2+2yy''+y'2=0⇒21+yy''+y'2=0⇒1+yy''+y'2=0
Hence, option B is correct.
If cos−1(x2−y2x2+y2)=loga then dydx =