If y=xx and d2ydx2−yx=1ydydx2 then =
xy
xx
yx
x
Explanation for the correct answer:
Find the dydx
The given function is y=xx
Taking logon both the sides,
logy=x⋅logx
Differentiate with respect to x,
1ydydx=logx+x1x=1+logx
dydx=xx[1+logx]
Hence, the correct option is B.
Fill in the blanks :
If x,y,z are three integer, then(x+y)+(___)=(____)+(____)