Checkout JEE MAINS 2022 Question Paper Analysis : Checkout JEE MAINS 2022 Question Paper Analysis :

If z1 and z2 are two roots of the equation z^2 + az + b= 0, z being a complex number. Further assume that the origin, z1 and z2 form an equilateral triangle. Then (1) a^2 = b (2) a^2 = 2b (3) a^2 = 3b (4) a^2 = 4b

Given z2 + az + b= 0,

z1+z2 = -a (sum of roots)

z1z2 = b (product of roots)

z2 = z1(cos π/3 + i sin π/3)

= z1(½ +i√3/2)

2z2-z1 = i√3z1

(2z2-z1 )2 = -3z12

z12+z22 = z1z2

So a2-2b = b

a2 = 3b

Hence option (3) is the answer.

Was this answer helpful?

 
   

0 (0)

(2)
(3)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published.

*

*

Ask
Question