Imaginary part of coshα+iβ-coshα-iβ
2sinhαsinhβ
2sinhαsinβ
2coshαcoshβ
2cosαcosβ
Explanation for the correct option.
Find the imaginary part.
Expand the expression coshα+iβ-coshα-iβ using the formula cosh(A+B)-cosh(A-B)=2sinhAsinhB.
coshα+iβ-coshα-iβ=2sinhαsinhiβ=2sinhα·isinβsinhiz=isinz=2sinhαsinβi
So the imaginary part of coshα+iβ-coshα-iβ is 2sinhαsinβ.
Hence, the correct option is B.
if tan^-1 (alpha + ibeta)= x+iy then x is equal to?