Question

In a common-base mode of a transistor, the collector current is $5.488mA$ for an emitter current of $5.60mA$. The value of the base current amplification factor ($\beta$) will be

• A. $47$
• B. $49$
• C. $51$
• D. $48$

Answer 1

The correct option is B

$49$

Step 1: Given:

Collector current $I_c=5.488mA$

Emitter current $I_e=5.60mA$

Step 2: Formula used

The base current $I_b=I_e-I_c$

$\beta =\frac{I_c}{I_b}$

Step 3: Finding base current

⇒ $I_b=5.60-5.488$

⇒ $I_b=0.112mA$

Step 4: Finding $\beta$

⇒ $\beta =\frac{5.488}{0.112}$

⇒ $\beta =49$

⇒ The base current amplification factor is $\beta =49$

Hence, the correct answer is option B.