Question

In a full-wave rectifier circuit operating from $50\mathrm{Hz}$mains frequency, the fundamental frequency in the ripple would be?

• A. $25\mathrm{Hz}$
• B. $50\mathrm{Hz}$
• C. $70.7\mathrm{Hz}$
• D. $100\mathrm{Hz}$

Answer 1

The correct option is D

$100\mathrm{Hz}$

Explanation for the correct :

Option(D):

Step 1:Given data:

In a full-wave rectifier circuit the input frequency is given as $\left(\mathrm{f}\right)$: $50\mathrm{Hz}$

Step 2:Formula applied:

For a full-wave rectifier, the output is considered for both the positive and negative cycle of input a.c.

So, the frequency of the ripple of the output is twice that of the input, which can be shown as:

The frequency of the ripple of the output can be given as:

${\mathrm{f}}^{\text{'}}=2\times \mathrm{f}$

Where $f^{\text{'}}=$ frequency of the ripple of the output

And $f^{}=$input frequency of the full-wave rectifier

Step 3:Calculation of the fundamental frequency in the ripple:

By applying the above formula the frequency of the ripple of the output can be calculated as:

$$\begin{gathered} {\mathrm{f}}^{\text{'}}=2\times 50\mathrm{Hz} \\ {\mathrm{f}}^{\text{'}}=100\mathrm{Hz} \end{gathered}$$

Hence, the fundamental frequency in the ripple would be $100\mathrm{Hz}.$