Question

In an electrical circuit, a battery is connected to pass $20\mathrm{C}$ of charge through it in a certain given time. The potential difference between two plates of the battery is maintained at $15\mathrm{V}.$ The work done by the battery is __________ J.

Answer 1

Step 1:Given data:

The charge of the battery is given as $\left(\mathrm{Q}\right)$ =$20\mathrm{C}$

The potential difference between the two plates of the battery is given as $\left(\mathrm{V}\right)$=$15\mathrm{V}.$

Step 2:Formula for calculating the work done:

The work done in moving the given charge through the circuit can be given as:

$\mathrm{Work}\left(\mathrm{W}\right)=\mathrm{Charge}\left(\mathrm{Q}\right)\times \mathrm{Potential}\mathrm{difference}\left(\mathrm{V}\right)$

Step 3:Calculating the work done:

By substituting the given values, we can calculate the work done by the battery as:

$$\begin{gathered} \mathrm{Work}\left(\mathrm{w}\right)=\mathrm{Q}.\mathrm{V} \\ \Rightarrow 20\times 15 \\ =300\mathrm{J} \end{gathered}$$

Hence, the work done by the battery is $300\mathrm{J}$.