a) 0.08o
b) 0.16o
c) 0.20o
d) 0.32o
Answer: b) 0.16o
Solution:
Δx = dsinθ = λ/2
sinθ = λ/2d
θ = sin-1(λ/2d)
= sin-1[(5460 x 10-10)/(2 x 0.1 x 10-3)]
= 0.16o
a) 0.08o
b) 0.16o
c) 0.20o
d) 0.32o
Answer: b) 0.16o
Solution:
Δx = dsinθ = λ/2
sinθ = λ/2d
θ = sin-1(λ/2d)
= sin-1[(5460 x 10-10)/(2 x 0.1 x 10-3)]
= 0.16o