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Question

In young's double slit experiment, the ratio of intensities of bright and dark bands is 16 which means:


A

The ratio of their amplitude is5.

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B

Intensities of individual sources are 25 and9 units respectively.

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C

The ratio of their amplitudes is 4.

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D

Intensities of individual sources are 4 and 3 units respectively.

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Solution

The correct option is B

Intensities of individual sources are 25 and9 units respectively.


Solution:

Step 1: Given information

The ratio of intensities of bright and dark bands=16.

ImaxImin=16

Step 2: Calculate the ratio of amplitude

LetI1 andI2 represent the intensities of individual sources with amplitudes A1 andA2, respectively.

Bright fringe intensity =Imax=(I1+I2)2…..(i)

Dark fringe intensity =Imin=(I1I2)2…..(ii)

From (i) and (ii),

ImaxImin=16 ….. (From given)

By solving (i) and (ii),

I1I2=53

I2=9unitsI1=25units

Furthermore, the amplitude is proportional to the intensity.

Therefore, the Ratio of amplitude=A1A2=I1I2=53.

Hence, the correct option is (B).


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