∫0π2cosx2dx=
1
-2
2
0
Explanation for the Correct Answer:
Finding the value of the given integration,
∫0π2cosx2dx=∫0π2cosx2dxcosx=cosx;-π2≤x≤π2=sinx2120π2=2sinπ4-sin0=212-0=2
Hence, option (C) is the correct answer.