Question

Is $\raisebox{1ex}{$J$}\!\left/ \!\raisebox{-1ex}{$Cm$}\right.$ unit of electric field?

Answer 1

Step 1: Given

Unit of Electric field = $\raisebox{1ex}{$J$}\!\left/ \!\raisebox{-1ex}{$Cm$}\right.$

Step 2: Formula

An electric field's force and potential energy are divided by the charge and thus measured $\raisebox{1ex}{$N$}\!\left/ \!\raisebox{-1ex}{$C$}\right.$.

Since,

$E=\frac{V}{r}$, Where, $E=$Electric field, $V=$Electric potential & $r=$Radius

Step 3: Calculation

$S.I.unitof$$E=$$\frac{S.I.unitofV}{S.I.unitofr}$,

$\Rightarrow S.I.unitofE=\frac{volt}{meter}$

$\Rightarrow \left(E\right)=\frac{V}{m}$, Where, $E\left(Energy\right)=q\left(Charge\right)\times V(potentialdifference)$

Hence unit of the electric field is $\frac{V}{m}$

Hence, $\raisebox{1ex}{$J$}\!\left/ \!\raisebox{-1ex}{$Cm$}\right.$ is not the unit of the electric field.