Let and be real numbers , if If is a root of , is a root of and . Then, the equation has a root that always satisfies
The explanation for the correct option:
Finding the equation has a root that always satisfies:
Given is a root of , and is a root of
Since is a root of
is a root of
Let
[from equation (i)]
[from equation (ii)]
must have a root lying in the open interval
Hence, the correct answer is option (C)