Evaluate : limitx→∞2x-33x-44x-55x-6
110
0
15
310
Explanation for the correct option:
Evaluating limitx→∞2x-33x-44x-55x-6
when we substitute limit it becomes the value ∞∞
=limitx→∞x2-3xx3-4xx4-5xx5-6x=limitx→∞x22-3x3-4xx24-5x5-6x=2-3∞3-4∞4-5∞5-6∞=2-03-04-05-0[∵1∞=0]=2×34×5=620=310
Hence, option (D) is the correct answer