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Question

Match theCpCv ratio for ideal gases with the different types of molecules:


Column 1Column 2

Monoatomic

75

Diatomic rigid molecules

97

Diatomic non rigid molecules

43

Triatomic rigid molecules

53

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Solution

Part A:

  1. For the monoatomic gas the degree of freedom is3.
  2. As we know,
    γ=CpCvγ=1+2f
    (where f=the degree of freedom, Cp=Specific heat capacity at constant pressure, Cv=Specific heat capacity at constant volume )
  3. The value ofCpCv is,
    γ=1+2f=1+23=53

Hence, (A) - (IV)

Part B:

  1. For the diatomic rigid molecules, the degree of freedom is5.
  2. As we know,
    γ=CpCvγ=1+2f
    (where f=the degree of freedom, Cp=Specific heat capacity at constant pressure, Cv=Specific heat capacity at constant volume )
  3. The value ofCpCv is,
    γ=1+2f=1+25=75

Hence, (B) - (I)

Part C:

  1. For the diatomic non-rigid molecules, the degree of freedom is7.
  2. As we know,
    γ=CpCvγ=1+2f
    (where f=the degree of freedom, Cp=Specific heat capacity at constant pressure, Cv=Specific heat capacity at constant volume )
  3. The value ofCpCv is,
    γ=1+2f=1+27=97

Hence, (C) - (II)

Part D:

  1. For the triatomic rigid molecules, the degree of freedom is6.
  2. As we know,
    γ=CpCvγ=1+2f
    (where f=the degree of freedom, Cp=Specific heat capacity at constant pressure, Cv=Specific heat capacity at constant volume )
  3. The value ofCpCv is,
    γ=1+2f=1+26=43

Thus, (D) - (III)

Hence, the correct answer is A-IV, B-I, C-2, D-III


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