  ##### JEE Questions

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Answer: Solution:Answer: Least k =87, Max k = 89Let total =100n(A)=89, n(B)=98max (n(A),n(B)) ≤ n(AUB) ≤ 10098 ≤ n(A)+n(B)-n(A n B) ≤ 100=> 98 ≤ 98 + 89- k ≤ 100Least k =87Max k = 89...
Answer: Solution:Answer: 5/9 Given: P(A) = p and P(B) = 2p P(A)-P(A∩B)+P(B)-P(A∩B) = 5/93p-2P(A∩B) = 5/90 ≤ P(A∩B) ≤ pFor maximum value: 3p - 2p = 5/9So, p = 5/9...
Answer: Solution:Answer: x = π/6Case 1: tan x ≥ 0cosx/(1+sinx ) = sinx/cosx⇒cos2x = sin2x+sinx⇒1-sin2x = sin2x + sinx⇒2 sin2x + sin x – 1 = 0⇒sin x = -1 ,1/2sin x = 1/2...
Answer: a. Cu2Cl2b. CuCl2c. AgBrd. ZnCl2Solution:Answer: (b)CuCl2 dissolves in water and gives coloured solutions...
Answer: a. Statement I is correct & Statement II is correctb. Statement I is correct & Statement II is incorrectc. Statement I is incorrect & Statement II is incorrectd. Statement I is...
Answer: a. (At constant temperature)And as we know, Molar Mass: CO2 > O2 > N2Therefore, Urms : UN2 > UO2 > UCO2Hence, option a) is correct...
Answer: Question: Choose the correct option for the given statements. Statement-I: Titration of a strong acid with a weak base uses methyl orange as an indicator. Statement-II: Titration of a weak acid...
Answer: Solution:Answer: (a)Bromination is highly selective.Reactivity order is: 3o > 2o > 1o...
Answer: Solution:Answer: (2.5)Potash alum = K2(SO4).Al2(SO4)3.24H2OMohr’s salt = (NH4)2Fe(SO4)2.6H2ORatio of water molecule = = 0.25 = 2.5 x 10-1Hence, the correct answer is 2.5...
Answer: a. Br2 / FeBr3, HNO3 / H2SO4, NaCN, H2O / H+b. HNO3 / H2SO4, Br2 / FeBr3, Mg / Ether, CO2, H3O+c. NaCN, H3O+, Br2 / FeBr3, H3O+ / CO2 / H2Od. HNO3 / H2SO4, Br2 / FeBr3 / NaCN/H2OSolution:Answer: (a)...
Answer: a. (1-x)2 f'(x) - 2(f(x)) 2 = 0b. (1-x) 2 f'(x) + 2(f(x)) 2= 0c. (1+x) 2 f'(x) - 2(f(x)) 2= 0d. (1+x) 2 f'(x)+2(f(x)) 2= 0Solution:Answer: (b)f(x) = = cos((2 tan-1(√x)= cos((cos-1 (((1 -...
Answer: a. Ca(HCO3)2,CaOb. CaO,Ca(HCO3)2c. CaCO3,Ca(HCO3)2d. Ca(HCO3)2,CaOSolution:Answer: (c)Ca(OH)2 (aq) + CO2(g) → CaCO3(s) + H2O(l)CaCO3(s) + H2O(l) + CO2(g) → Ca(HCO3)2(aq)Hence, the...
Answer: Solution:Answer: 16(OP) 2 + (AP) 2 + (PC) 2 + (PB) 2=18=> x2 + y2 + x2 + (y - 1) 2 + (x - 1) 2 + y2 + (x - 1) 2 + (y - 1) 2 =18=> 4x2 + 4y2 - 4x - 4y=14=> x2 + y2 - x - y=7/2=>...
Answer: a. ΔH < 0, ΔS < 0b. ΔH < 0, ΔS > 0c. ΔH > 0, ΔS > 0d. ΔH = 0, ΔS > 0Solution:Answer: (a)During adsorption, there is always a...
Answer: Solution:Answer: 40loge (x+y) = 4xyor 1/((x + y)) [1 + (dy/dx)] = 4[x (dy/dx) + y]or 1 + (dy/dx) = 4(x + y) [x (dy/dx) + y]⋯(i)If x = 0, then y = 1From (i)1 + dy/dx = 4(0 + 1)[0 + 1] = 4Or dy/dx...  