Pressure inside two soap bubbles are 1.01 and 1.02 atmosphere, respectively. The ratio of their volumes is:

1) 4 : 1

2) 2 : 1

3) 0.8 : 1

4) 8 : 1

Solution:

Answer. 4

\(P_{in}=P_{0}+\frac{4T}{R_{1}}\),

\(1.01=1+\frac{4T}{R_{1}}\),

\(0.01=\frac{4T}{R_{1}}\),

\(0.02=\frac{4T}{R_{2}}\),

\(\frac{1}{2}=\frac{R_{2}}{R_{1}}\),

\(\frac{V_{1}}{V_{2}}=\frac{8}{1}\)

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